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2.5x+1.8x^2=7
We move all terms to the left:
2.5x+1.8x^2-(7)=0
a = 1.8; b = 2.5; c = -7;
Δ = b2-4ac
Δ = 2.52-4·1.8·(-7)
Δ = 56.65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{56.65}}{2*1.8}=\frac{-2.5-\sqrt{56.65}}{3.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{56.65}}{2*1.8}=\frac{-2.5+\sqrt{56.65}}{3.6} $
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